pc386 BSP on board with UMA
Chris Johns
chrisj at rtems.org
Thu Dec 10 00:16:43 UTC 2009
Joel Sherrill wrote:
> Hi,
>
> I have been debugging a lock up during initialization
> on an embedded PC with 1GB RAM but the last part is
> reserved for video, etc.. See Section 5.4 in this
> manual.
>
> =================================================================
> http://www.intel.com/assets/pdf/datasheet/252615.pdf
>
> Voids of physical addresses that are not accessible as general system
> memory and reside within
> system memory address range (< TOM) are created for SMM-mode and legacy
> VGA graphics
> compatibility. It is the responsibility of BIOS to properly initialize
> these regions. The number
> of UMA options has been extended. Allocation is at a fixed address in
> terms of rigid positioning
> of UMA system memory TOM-TSEG-UMA(size), but it is mapped at any
> available address by
> a PCI allocation algorithm. GMADR and MMADR are requested through BARs.
> The following table details the location and attributes of the regions.
>
> Table 33. Pre-allocated System Memory
> System Memory Segments Attributes Comments
> 00000000H - 03E7FFFFH R/W Available system memory 62.5 -MB
> 03E80000H - 03F7FFFFH R/W Pre-allocated Graphics VGA memory
> 1-MB (or 4/8/16/32- MB) when IGD is
> enabled
> 03F80000H - 03FFFFFFH SMM Mode Only - CPU Reads TSEG Address Range
> 03F80000H - 03FFFFFFH SMM Mode Only - CPU Reads TSEG Pre-allocated
> system memory
>
> =================================================================
>
Interesting manual. Seems to assume you know what TSEG, SMM etc is.
> The memory sizing algorithm finds 1007MB on this board.
What memory sizing code is this ?
> But
> if you clear all of that memory, the system locks up. If I
> decrease that to 1004MB, things work. My reading of the
> above is that we shouldn't touch the last 64MB RAM.
>
> Does that make sense? Is there some way to know this?
>
I have not followed in detail the size you need to leave, but I would
have thought the BIOS would have taken this into account for you.
Chris
> Help... :)
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